Practice portal › Electromagnetic Induction › Mutual Inductance
Asked in GUJCET 2013 · Standard coil geometries
Idea: pass a current I through the large loop, find the flux it sends through the small loop, then M = Φ/I.
Field at the centre of the large loop: B = (μ₀ I)/(2R).
Since R r, this field is nearly uniform over the small loop, so Φ = B·π r² = (μ₀ Iπ r²)/(2R).
M = Φ/I = (μ₀π r²)/(2R).
So M ∝ (r²)/R.
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