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Asked in GUJCET 2025 · Mutual inductance and induced EMF
Given: M=2 H, Δ I=30-0=30 A, Δ t=0.15 s.
Idea: mutual inductance is defined by N₂Φ₂=MI₁, so the flux linkage with the second coil follows the current in the first.
The change is therefore Δ(N₂Φ₂)=M Δ I₁=2×30; the time does not enter a flux linkage at all.
So the change of flux linkage is 60 Wb.
(The time would matter only for the emf, (60)/(0.15)=400 V, which the question does not ask for.)
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