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Asked in GUJCET 2022 · Mutual inductance and induced EMF
Given: M=1.5 H, Δ I=10-0=10 A, Δ t=0.5 s.
Idea: N₂Φ₂=MI₁, so the change of flux linkage is M Δ I₁; the time does not enter.
Δ(N₂Φ₂)=1.5×10.
So the change of flux linkage is 15 Wb. (The average emf would be (15)/(0.5)=30 V.)
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