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Asked in RS Academy GUJCET booklet · Null point
Given: charges q and 4q (same sign) 30 cm apart.
Idea: for like charges the two fields point in opposite directions only between the charges, so the null point lies between them, nearer the smaller charge.
Let the point be x from q, so 30-x from 4q (in cm):
(kq)/(x²)=(k(4q))/((30-x)²)
(30-x)/x=√4=2⇒30-x=2x⇒ x=10 cm
So the point is 10 cm from q, that is 20 cm from 4q.
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