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Two point charges q and 4q are kept 30 cm apart. At a distance ......., on the straight line joining them, the intensity of the electric field is zero.

Asked in RS Academy GUJCET booklet · Null point

Answer: (1) 20 cm from 4q

Step-by-step solution

Given: charges q and 4q (same sign) 30 cm apart.

Idea: for like charges the two fields point in opposite directions only between the charges, so the null point lies between them, nearer the smaller charge.

Let the point be x from q, so 30-x from 4q (in cm):

(kq)/(x²)=(k(4q))/((30-x)²)

(30-x)/x=√4=2⇒30-x=2x⇒ x=10 cm

So the point is 10 cm from q, that is 20 cm from 4q.

Why the other options are wrong

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