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Asked in RS Academy GUJCET booklet · Field of discrete charges
Idea: use superposition with the complete polygon.
With a charge Q on all n corners, the field at the centre is zero by symmetry.
The actual arrangement = complete polygon + a charge -Q at the empty corner.
So the field at the centre equals the field of that -Q alone: magnitude (kQ)/(r²), directed towards the empty corner.
So the field at the centre is (kQ)/(r²), whatever the value of n.
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