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Asked in GUJCET 2021 · Infinite sheet and sheet combinations
Given: σ=17.7×10⁻²² C/m² on each inner face, both of the same sign; ε₀=8.85×10⁻¹² C² N⁻¹ m⁻².
Idea: treat each charged face as a large sheet, which gives σ/(2ε₀) on either side, directed away from it (for positive σ).
Beyond the second plate both fields point the same way, away from the pair, so they add:
E=σ/(2ε₀)+σ/(2ε₀)=σ/(ε₀)
E=(17.7×10⁻²²)/(8.85×10⁻¹²)=2×10⁻¹⁰ N C⁻¹
(Between the plates the two fields point in opposite directions and cancel.)
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