Practice portal › Electric Charge and Properties › Field of Continuous Charge Distributions

A circle of radius a has a charge density λ = λ₀ cos²θ on its circumference. What will be the total charge on the circle?

Asked in GUJCET 2008 · Ring, arc and disc

Answer: (1) π aλ₀

Step-by-step solution

Given: λ = λ₀ cos²θ on a circle of radius a.

Idea: total charge Q = ∮λ dl, with dl = a dθ.

Q = ∫₀^2πλ₀ cos²θ a dθ = aλ₀∫₀^2π(1+cos 2θ)/2 dθ

Q = aλ₀[θ/2 + (sin 2θ)/4]₀^2π = π aλ₀

Check: the average of cos²θ over a full turn is 1/2, and 1/2×2π aλ₀ = π aλ₀.

So the total charge is π aλ₀.

Why the other options are wrong

More Field of Continuous Charge Distributions questionsAll Field of Continuous Charge Distributions questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer