Practice portal › Electric Charge and Properties › Field of Continuous Charge Distributions
Asked in GUJCET 2015 · Rod and line charge
Idea: split the rod into small elements, each a point charge. Every element pushes on q along the axis, so the forces simply add.
Charge per unit length: λ=Q/L. An element dx at distance x from q carries λ dx.
dF=(Kqλ dx)/(x²), with x running from r (near end) to r+L (far end).
F=Kqλ∫ᵣ^r+L(dx)/(x²)=Kqλ(1/r-1/(r+L))=Kqλ L/(r(r+L))
F=(KQq)/(r(r+L))
Check: when r is much larger than L this becomes (KQq)/(r²), the force between two point charges, as it should.
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