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Asked in GUJCET 2014 · de Broglie relation and its graphs
Given: m = 100 g = 0.1 kg, v = 36 km h⁻¹ = 36×(1000)/(3600) = 10 m s⁻¹.
Idea: de Broglie wavelength λ = h/(mv).
mv = 0.1×10 = 1 kg m s⁻¹
λ = (6.626×10⁻³⁴)/1 = 6.626×10⁻³⁴ m
So λ is of the order of 10⁻³⁴ m -- hopelessly small to observe for an everyday object.
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