Practice portal › Dual Nature of Matter and Radiation › Photon Energy, Number of Photons and Intensity
Asked in GSEB Board March 2018 · Photon energy, momentum and mass
Given: E = hf and P = h/λ.
Idea: divide the two so that Planck's constant cancels.
E/P = hf×λ/h = fλ
For any wave, frequency × wavelength = wave speed, so fλ = c.
So the speed of light is c = E/P.
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