Practice portal › Dual Nature of Matter and Radiation › Photon Energy, Number of Photons and Intensity
Asked in GSEB Board August 2020 · Photon energy, momentum and mass
Given: f = 6.0×10⁸ MHz = 6.0×10¹⁴ Hz; take h = 6.63×10⁻³⁴ J s.
Idea: one photon carries E = hf. The power is not needed for this part.
E = 6.63×10⁻³⁴×6.0×10¹⁴
E = 3.98×10⁻¹⁹ J, which is about 2.49 eV.
(The power gives the photon rate: (2×10⁻³)/(3.98×10⁻¹⁹) ≈ 5.0×10¹⁵ photons per second.)
So each photon has energy 3.98×10⁻¹⁹ J.
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