Practice portal › Dual Nature of Matter and Radiation › Comparing de Broglie Wavelengths of Particles
Asked in GUJCET 2023 · Same or changed energy
Given: the same kinetic energy K for all three particles.
Idea: λ = h/(√2mK), so at fixed K, λ ∝ 1/(√m): the lightest particle has the longest wavelength.
Masses: mₑ mₚ < m_α ≈ 4mₚ.
The electron is about 1836 times lighter than the proton, so λₑ ≈ 43 λₚ.
So the electron has the longest de Broglie wavelength.
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