Practice portal › Dual Nature of Matter and Radiation › Comparing de Broglie Wavelengths of Particles
Asked in RS Academy GUJCET booklet · Equal wavelengths and equal speeds
Idea: de Broglie wavelength λ = h/p depends only on the momentum p.
If λₚ = λ_α, then h/(pₚ) = h/(p_α), so pₚ = p_α.
The masses differ (m_α ≈ 4mₚ), so their velocities and kinetic energies differ.
So the quantity that must be the same is the momentum.
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