To reduce the de Broglie wavelength of an electron from 10⁻¹⁰ m to 0.5×10⁻¹⁰ m, its energy should be .

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(1) increased to 4 times. Given: λ₁ = 10⁻¹⁰ m and λ₂ = 0.5×10⁻¹⁰ m, so the wavelength must halve. Idea: λ = h/(√2mK), so for the same electron K ∝ 1/(λ²). (K₂)/(K₁) = ((λ₁)/(λ₂))² = (1/(0.5))² = 4 Halving the wavelength needs four times the energy. So the energy should be increased to 4 times.

To reduce the de Broglie wavelength of an electron from 10⁻¹⁰ m to 0.5×10⁻¹⁰ m, its energy should be ______.

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Why the other options are wrong