Practice portal › Dual Nature of Matter and Radiation › de Broglie Wavelength and Accelerating Potential
Asked in GUJCET 2020 · Accelerated through a potential difference
Given: V = 100 V.
Idea: an electron accelerated through V has p = √2meV, so λ = h/(√2meV).
Putting in h, m and e: λ = (1.227)/(√V) nm.
λ = (1.227)/(√100) = (1.227)/(10) = 0.1227 nm
So λ ≈ 0.123 nm.
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