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What is the de Broglie wavelength associated with an electron accelerated through a potential difference of 64 V? (Take h = 6.63×10⁻³⁴ J s.)

Asked in GUJCET 2021 · Accelerated through a potential difference

• (1) 1.23 A
• (2) 1.87 A
• (3) 1.53 A
• (4) 1.98 A

Step-by-step solution

Why the other options are wrong

• (1) 1.23 A is the wavelength for 100 V, since (12.27)/(√100) = 1.23, the familiar textbook example. Here V = 64 V, so divide by √64 = 8.
• (2) No single slip gives 1.87 A. Sanity check: (12.27)/(√64) = (12.27)/8 ≈ 1.53 A.
• (4) No single slip gives 1.98 A; even dropping the factor 2 under the root gives 2.17 A. Sanity check: (12.27)/8 ≈ 1.53 A.

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