Practice portal › Dual Nature of Matter and Radiation › de Broglie Wavelength and Accelerating Potential
Asked in GUJCET 2023 · Accelerated through a potential difference
Given: accelerating potential V = 64 V.
Idea: the electron gains kinetic energy K = eV, so λ = h/(√2meV), which works out to λ = (12.27)/(√V) A.
λ = (12.27)/(√64) = (12.27)/8 = 1.53 A
Check directly: √2×9.1×10⁻³¹×1.6×10⁻¹⁹×64 = 4.32×10⁻²⁴ kg m s⁻¹, and (6.63×10⁻³⁴)/(4.32×10⁻²⁴) = 1.53×10⁻¹⁰ m.
So λ = 1.53 A.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer