Practice portal › Dual Nature of Matter and Radiation › Comparing de Broglie Wavelengths of Particles

The de Broglie wavelength of an atom at absolute temperature T will be ______. (m = mass of the atom, k_B = Boltzmann constant)

Asked in GUJCET 2015 · Matter waves in other settings

Answer: (1) h/(√3mk_BT)

Step-by-step solution

Given: an atom of mass m in thermal equilibrium at temperature T.

Idea: its mean translational kinetic energy is K = 3/2k_BT.

Momentum: p = √2mK = √2m·3/2k_BT = √3mk_BT

λ = h/p = h/(√3mk_BT)

So the de Broglie wavelength is h/(√3mk_BT).

Why the other options are wrong

More Comparing de Broglie Wavelengths of Particles questionsAll Comparing de Broglie Wavelengths of Particles questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer