Practice portal › Dual Nature of Matter and Radiation › Comparing de Broglie Wavelengths of Particles
Asked in GUJCET 2016; GUJCET 2019 · Same or changed energy
Given: λ₁ = 0.5×10⁻¹⁰ m and λ₂ = 1×10⁻¹⁰ m, so λ₂ = 2λ₁.
Idea: λ = h/p = h/(√2mK), so K = (h²)/(2mλ²) ∝ 1/(λ²).
(K₂)/(K₁) = ((λ₁)/(λ₂))² = (1/2)² = 1/4
So the energy must be decreased to one-fourth of its value.
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