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The kinetic energies of photoelectrons emitted from a metal are k₁ and k₂ when it is irradiated with light of wavelengths λ₁ and λ₂ respectively. The work function of the metal is ______.

Asked in GUJCET 2013 · Work function and the photoelectric equation

Answer: (4) (k₁λ₁-k₂λ₂)/(λ₂-λ₁)

Step-by-step solution

Given: kinetic energy k₁ with wavelength λ₁ and k₂ with λ₂, on the same metal.

Idea: write Einstein's equation for each light and eliminate hc.

(hc)/(λ₁) = φ₀ + k₁, so hc = λ₁(φ₀ + k₁)

(hc)/(λ₂) = φ₀ + k₂, so hc = λ₂(φ₀ + k₂)

Equate: λ₁φ₀ + k₁λ₁ = λ₂φ₀ + k₂λ₂

φ₀(λ₂ - λ₁) = k₁λ₁ - k₂λ₂

φ₀ = (k₁λ₁ - k₂λ₂)/(λ₂ - λ₁)

Check: φ₀ = 2 eV, λ₁ = 248 nm (k₁ = 3 eV), λ₂ = 310 nm (k₂ = 2 eV) give (744 - 620)/(62) = 2 eV.

Why the other options are wrong

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