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Photons of energy 1 eV and 2.5 eV successively illuminate a metal whose work function is 0.5 eV. The ratio of the maximum speeds of the emitted electrons is ______.

Asked in GUJCET 2015; GUJCET 2017 · Speed and kinetic energy of the photoelectrons

Answer: (2) 1:2

Step-by-step solution

Given: photon energies E₁ = 1 eV and E₂ = 2.5 eV; work function φ₀ = 0.5 eV.

Idea: 1/2mvₘₐₓ² = E - φ₀, so vₘₐₓ ∝ √E - φ₀.

K₁ = 1 - 0.5 = 0.5 eV and K₂ = 2.5 - 0.5 = 2.0 eV

(v₁)/(v₂) = √(0.5)/(2.0) = √1/4 = 1/2

So the ratio of the maximum speeds is 1:2.

Why the other options are wrong

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