Practice portal › Dual Nature of Matter and Radiation › Einstein's Photoelectric Equation and Work Function
Asked in GUJCET 2015; GUJCET 2017 · Speed and kinetic energy of the photoelectrons
Given: photon energies E₁ = 1 eV and E₂ = 2.5 eV; work function φ₀ = 0.5 eV.
Idea: 1/2mvₘₐₓ² = E - φ₀, so vₘₐₓ ∝ √E - φ₀.
K₁ = 1 - 0.5 = 0.5 eV and K₂ = 2.5 - 0.5 = 2.0 eV
(v₁)/(v₂) = √(0.5)/(2.0) = √1/4 = 1/2
So the ratio of the maximum speeds is 1:2.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer