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The threshold wavelength for lithium metal is 6250 A. For photoemission, the wavelength of the incident light must be ______.

Asked in GUJCET 2014 · Threshold frequency and wavelength

Answer: (4) equal to or less than 6250 A

Step-by-step solution

Idea: a photon can free an electron only if (hc)/λ ≥ φ₀ = (hc)/(λ₀).

This gives λ ≤ λ₀: a shorter wavelength means a more energetic photon.

Here λ₀ = 6250 A.

So the incident wavelength must be equal to or less than 6250 A.

Why the other options are wrong

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