Practice portal › Dual Nature of Matter and Radiation › Einstein's Photoelectric Equation and Work Function
Asked in GUJCET 2011 · Speed and kinetic energy of the photoelectrons
Given: work function φ₀; photon energy 3φ₀ gives v₁ = 6×10⁶ m s⁻¹; new photon energy 9φ₀.
Idea: 1/2mvₘₐₓ² = E - φ₀, so vₘₐₓ ∝ √E - φ₀.
K₁ = 3φ₀ - φ₀ = 2φ₀ and K₂ = 9φ₀ - φ₀ = 8φ₀.
(v₂)/(v₁) = √(8φ₀)/(2φ₀) = √4 = 2
v₂ = 2×6×10⁶ = 12×10⁶ m s⁻¹
So the new maximum velocity is 12×10⁶ m s⁻¹.
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