Practice portal › Current Electricity › Combination of Resistors
Asked in RS Academy GUJCET booklet · Symmetric and complex networks
Given: resistance R cut into 20 equal pieces, each of resistance R/(20).
Idea: find the resistance of each group, then add the two groups in series.
Series group: 10×R/(20) = R/2.
Parallel group: ten equal resistors R/(20) in parallel give 1/(10)×R/(20) = R/(200).
Total: R/2 + R/(200) = (100R + R)/(200) = (101R)/(200).
So the effective resistance is (101R)/(200).
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