Practice portal › Current Electricity › Combination of Resistors
Asked in RS Academy GUJCET booklet · Symmetric and complex networks
Given (figure): five resistors, each r. Points T and M are joined by a plain wire, so they are one node.
Between X and that node the top-left and middle-left resistors are in parallel: (r· r)/(r + r) = r/2.
Between that node and Y the top-right and middle-right resistors are in parallel: r/2.
The two pairs are in series: r/2 + r/2 = r.
The bottom resistor r also joins X to Y, in parallel with this: R_XY = (r· r)/(r + r) = r/2.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer