Practice portal › Current Electricity › Cells, EMF and Internal Resistance

The internal resistance of a battery of 2 V terminal voltage is 0.2 Ω. If the current flowing through the battery is 0.5 A, what will be the emf of the battery?

Asked in GSEB Board March 2020 (old course) · Terminal voltage and internal resistance

Answer: (3) 2.1 V

Step-by-step solution

Given: terminal voltage V=2 V, internal resistance r=0.2 Ω, current I=0.5 A.

Idea: while a battery drives current, part of its emf is used up inside it, so V=ε-Ir.

Internal drop: Ir=0.5×0.2=0.1 V.

ε=V+Ir=2+0.1.

ε=2.1 V.

Only a battery being charged has a terminal voltage above its emf (then ε=V-Ir=1.9 V); nothing in the question says it is being charged.

Why the other options are wrong

More Cells, EMF and Internal Resistance questionsAll Cells, EMF and Internal Resistance questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer