At what temperature would the resistance of a copper conductor be double its resistance at 0°C? Given: α for copper is 3.9×10⁻³ °C⁻¹.

Question

Accepted Answer

(1) 256.4°C. Given: Rₜ = 2R₀ and α = 3.9×10⁻³ °C⁻¹. Idea: Rₜ = R₀(1 + α t), where t is measured in °C from 0°C. 2R₀ = R₀(1 + α t) ⇒ α t = 1. t = 1/α = 1/(3.9×10⁻³) = 256.4°C. So the resistance doubles at about 256.4°C.

At what temperature would the resistance of a copper conductor be double its resistance at 0°C? Given: α for copper is 3.9×10⁻³ °C⁻¹.

Step-by-step solution

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