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A resistive wire is stretched till its length is increased by 100%. Due to the consequent decrease in diameter, the change in the resistance of the stretched wire will be ______.

Asked in GSEB Board July 2015 · Resistance of a wire and stretching

Answer: (1) 300%

Step-by-step solution

Given: the length is increased by 100%, so ℓ' = 2ℓ; the volume of the wire does not change.

Idea: R = (ρℓ)/A, and constant volume means Aℓ = A'ℓ', so A' = A/2.

R' = (ρ(2ℓ))/(A/2) = 4 (ρℓ)/A = 4R.

Change = (R' - R)/R×100% = (4 - 1)×100% = 300%.

So the resistance increases by 300%.

Why the other options are wrong

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