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Asked in GUJCET 2025 · Energy levels and ionisation
Given: total energy E=-13.6 eV; the blank is to be filled in the order potential energy first, kinetic energy second.
Idea: a circular Coulomb orbit splits its energy in a fixed way, U=2E and K=-E.
U=2×(-13.6)=-27.2 eV.
K=-(-13.6)=+13.6 eV.
Check: U+K=-27.2+13.6=-13.6 eV=E, and the kinetic energy comes out positive, as any kinetic energy must.
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