Practice portal › Atoms › Bohr Model of the Hydrogen Atom
Asked in RS Academy GUJCET booklet · Bohr's rules in other systems
Idea: for a one-electron (hydrogen-like) system the Bohr radius of the nth orbit is rₙ=(n²)/Za₀, with a₀=0.53 A.
The orbit is fixed at n=2, so r₂=(4a₀)/Z: the larger the nuclear charge, the smaller the orbit.
Mg¹¹⁺ is magnesium (Z=12) with 11 of its 12 electrons removed, so it is hydrogen-like and has the largest Z on the list.
r₂=(4×0.53)/(12)=0.18 A, against 2.12 A for hydrogen and 1.06 A for He⁺.
So the second orbit is smallest in Mg¹¹⁺.
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