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Asked in GUJCET 2026 · Energy levels and ionisation
Given: the ground-state total energy E=-13.6 eV.
Idea: for a circular Coulomb orbit the kinetic energy is K=-E and the potential energy is U=2E.
K=+13.6 eV and U=2×(-13.6)=-27.2 eV.
K/U=(13.6)/(-27.2)=-1/2.
The sign carries the physics: the kinetic energy is positive, the potential energy negative and twice as big, so the ratio is negative and of size one half.
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