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The ground state energy of hydrogen atom is -13.6 eV. What is the ratio of kinetic energy and potential energy of the electron of this state?

Asked in GUJCET 2026 · Energy levels and ionisation

Answer: (1) -1/2

Step-by-step solution

Given: the ground-state total energy E=-13.6 eV.

Idea: for a circular Coulomb orbit the kinetic energy is K=-E and the potential energy is U=2E.

K=+13.6 eV and U=2×(-13.6)=-27.2 eV.

K/U=(13.6)/(-27.2)=-1/2.

The sign carries the physics: the kinetic energy is positive, the potential energy negative and twice as big, so the ratio is negative and of size one half.

Why the other options are wrong

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