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In Geiger-Marsden scattering experiment the thickness of a thin foil of gold is ________ m.

Asked in GUJCET 2024 · Rutherford's model and its limits

Answer: (3) 2.1 × 10⁻⁷

Step-by-step solution

Idea: the foil has to be thin enough that an α-particle crossing it meets at most one nucleus closely, so every large deflection can be read as a single scattering event rather than a sum of small ones.

Geiger and Marsden used a gold foil of thickness 2.1×10⁻⁷ m, about 0.21 μm — only a few hundred atoms deep.

Gold suits the job twice over: it can be beaten this thin, and its heavy nucleus (Z=79) deflects α-particles strongly.

So the thickness is 2.1×10⁻⁷ m.

Why the other options are wrong

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