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In Rutherford's α-scattering experiment, what will be the correct angle of scattering for impact parameter b=0?

Asked in GUJCET 2007 · Rutherford's model and its limits

Answer: (1) 180°

Step-by-step solution

Idea: the impact parameter and the scattering angle are linked by b=(Ze² cot(θ/2))/(4πε₀E), where E is the α-particle's kinetic energy.

With b=0 the right-hand side must vanish, so cot θ/2=0.

cot is zero at 90°, so θ/2=90° and θ=180°.

Physically, a particle aimed dead centre at the nucleus is stopped and sent straight back along its own path.

Why the other options are wrong

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