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What is the difference of angular momenta of an electron between two consecutive orbits in hydrogen atom?

Asked in GUJCET 2009 · Postulates, radius, speed and angular momentum

Answer: (2) h/(2π)

Step-by-step solution

Idea: Bohr's condition quantises angular momentum, Lₙ=(nh)/(2π).

For consecutive orbits n and n+1: Lₙ₊₁-Lₙ=((n+1)h)/(2π)-(nh)/(2π).

Δ L=h/(2π).

The step is the same between any two neighbouring orbits.

Why the other options are wrong

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