Practice portal › Atoms › Bohr Model of the Hydrogen Atom

A charge q₂ of mass m revolves around a stationary charge q₁ in a circular orbit of radius r. The orbital period of q₂ would be _____

Asked in GUJCET 2011 · Postulates, radius, speed and angular momentum

Answer: (1) [(4π²mr³)/(kq₁q₂)]^1/2

Step-by-step solution

Idea: the Coulomb attraction supplies the centripetal force; here k=1/(4πε₀) and q₁q₂ stands for the size of the product.

(mv²)/r=(kq₁q₂)/(r²), so v²=(kq₁q₂)/(mr).

Period: T=(2π r)/v, so T²=(4π²r²)/(v²)=(4π²r²· mr)/(kq₁q₂).

T²=(4π²mr³)/(kq₁q₂), so T=[(4π²mr³)/(kq₁q₂)]^1/2.

This is Kepler's third law in electrical form: T²∝ r³.

Why the other options are wrong

More Bohr Model of the Hydrogen Atom questionsAll Bohr Model of the Hydrogen Atom questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer