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Asked in GSEB Board March 2020 (old course) · Phase relationships and phasors
In a series circuit the same current I flows through L and C.
The voltage across L leads I by 90°; the voltage across C lags I by 90°. On the phasor diagram they point in opposite directions.
Net voltage: V=I(X_C-X_L), pointing along the capacitor's phasor because X_C>X_L.
So the source voltage lags the current by 90°, just as for a pure capacitor.
Equivalently, the current leads the voltage by π/2.
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