Practice portal › Alternating Current › AC Through R, L and C
Asked in GSEB Board March 2020 · Reactance and frequency
Given: C=15 μF=15×10⁻⁶ F and f=50 Hz. The 220 V is not needed for the reactance.
Idea: a capacitor opposes a.c. through its reactance X_C=1/(ω C)=1/(2π fC).
2π fC=2×3.14×50×15×10⁻⁶=4.71×10⁻³.
X_C=1/(4.71×10⁻³)≈212 Ω.
So the capacitive reactance is about 212 Ω.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer