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An alternating voltage given as V = 200√2 sin(100t) V is applied to a capacitor of 5 μF. The current reading of the ammeter will be equal to ______ mA.

Asked in GSEB Board July 2018 · Reactance and frequency

• (1) 80
• (2) 20
• (3) 40
• (4) 100

Step-by-step solution

Why the other options are wrong

• (1) No single slip gives 80 mA; it is the reading a 4 μF capacitor would give. Sanity check: 200×100×5×10⁻⁶ = 0.1 A.
• (2) No single slip gives 20 mA from these values; it is the reading for a 1 μF capacitor. With 5 μF the current is five times larger.
• (3) No single slip gives 40 mA; it is the reading for 2 μF. Sanity check: X_C = 2000 Ω and (200 V)/(2000 Ω) = 0.1 A.

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