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The number of turns in the coil of an A.C. generator is 100 and its cross-sectional area is 2.5 m². The coil is revolving in a uniform magnetic field of strength 0.3 T with a uniform angular velocity of 60 rad s⁻¹. The maximum value of the emf produced is _____.

Asked in GUJCET 2017 · AC generator, motors and devices

Answer: (2) 4.50 kV

Step-by-step solution

Given: N=100, A=2.5 m², B=0.3 T and ω=60 rad s⁻¹.

Idea: the flux linkage of the rotating coil is NBA cos ω t, so the induced emf is ε=NBAω sin ω t.

The emf is largest when sin ω t=1, with the plane of the coil parallel to the field: ε₀=NBAω.

ε₀=100×0.3×2.5×60=4500 V.

So the maximum emf is 4.50 kV.

Why the other options are wrong

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