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Asked in GUJCET 2017 · AC generator, motors and devices
Given: N=100, A=2.5 m², B=0.3 T and ω=60 rad s⁻¹.
Idea: the flux linkage of the rotating coil is NBA cos ω t, so the induced emf is ε=NBAω sin ω t.
The emf is largest when sin ω t=1, with the plane of the coil parallel to the field: ε₀=NBAω.
ε₀=100×0.3×2.5×60=4500 V.
So the maximum emf is 4.50 kV.
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