An alternating voltage V=100√2 sin(100t) V is applied to a capacitor of 1 μF. The current reading of the ammeter will be equal to .

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(2) 10 mA. Given: V=100√2 sin(100t), so V₀=100√2 V and ω=100 rad s⁻¹; C=1 μF=10⁻⁶ F. Idea: an a.c. ammeter reads the r.m.s. current. Vᵣₘₛ=(V₀)/(√2)=100 V. X_C=1/(ω C)=1/(100×10⁻⁶)=10⁴ Ω. Iᵣₘₛ=(Vᵣₘₛ)/(X_C)=(100)/(10⁴)=0.01 A=10 mA. So the ammeter reads 10 mA.

An alternating voltage V=100√2 sin(100t) V is applied to a capacitor of 1 μF. The current reading of the ammeter will be equal to ______.

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