Practice portal › Alternating Current › Series LCR: Impedance and Phase
Asked in GUJCET 2015 · Impedance and phase angle
Given: f=(25)/π Hz, R=100 Ω, L=2 H.
Angular frequency: ω=2π f=2π×(25)/π=50 rad s⁻¹.
Inductive reactance: X_L=ω L=50×2=100 Ω.
Idea: in a series R–L circuit the voltage leads the current by φ, where tan φ=(X_L)/R.
tan φ=(100)/(100)=1⇒φ=45°.
So the phase difference is 45°.
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