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A current of frequency (50)/π Hz is passing through an A.C. circuit having a series combination of resistance R = 100 Ω and inductor L = √3 H. The phase difference between the voltage and current is ______.

Asked in GUJCET 2016 · Impedance and phase angle

Answer: (1) 60°

Step-by-step solution

Given: f = (50)/π Hz, R = 100 Ω, L = √3 H.

X_L = 2π fL = 2π×(50)/π×√3 = 100√3 Ω ≈ 173 Ω.

Idea: in an L-R circuit the voltage leads the current by φ with tan φ = (X_L)/R.

tan φ = (100√3)/(100) = √3, so φ = 60°.

Why the other options are wrong

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