Practice portal › Alternating Current › Series LCR: Impedance and Phase
Asked in GUJCET 2016 · Impedance and phase angle
Given: f = (50)/π Hz, R = 100 Ω, L = √3 H.
X_L = 2π fL = 2π×(50)/π×√3 = 100√3 Ω ≈ 173 Ω.
Idea: in an L-R circuit the voltage leads the current by φ with tan φ = (X_L)/R.
tan φ = (100√3)/(100) = √3, so φ = 60°.
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