At time t=0 s the voltage of an A.C. generator starts from 0 V and becomes 2 V at time t=1/(100π) s. The voltage keeps on increasing up to 100 V, after which it starts to decrease. Find the frequency of the generator.

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(2) 1 Hz. Idea: the generator voltage is V=V₀ sin ω t. It starts from zero, and its largest value is the peak, so V₀=100 V. At t=1/(100π) s: 2=100 sin ω t, so sin ω t=0.02. The angle is small, so sin ω t≈ω t and ω t=0.02. ω=0.02×100π=2π rad s⁻¹. f=ω/(2π)=(2π)/(2π)=1 Hz. So the frequency of the generator is 1 Hz.

At time t=0 s the voltage of an A.C. generator starts from 0 V and becomes 2 V at time t=1/(100π) s. The voltage keeps on increasing up to 100 V, after which it starts to decrease. Find the frequency of the generator.

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