Practice portal › Alternating Current › Alternating Quantities: RMS and Mean
Asked in GUJCET 2009 · Instantaneous values and timing
Given: f=50 Hz, so the period is T=1/(50) s=20 ms.
Idea: starting from zero, I=I₀ sin ω t, and the rms value is (I₀)/(√2).
I₀ sin ω t=(I₀)/(√2)⇒sin ω t=1/(√2)⇒ω t=π/4.
t=π/(4ω)=π/(4×2π f)=1/(8f)=T/8=(20 ms)/8=2.5 ms.
So the time is 2.5 ms.
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