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Asked in CBSE AIPMT 1991 · Percentage error in a derived quantity
Given: m=22.42 g with Δ m=0.01 g, V=4.7 cc with Δ V=0.1 cc.
ρ=m/V
(Δρ)/ρ=(Δ m)/m+(Δ V)/V
(0.01)/(22.42)×100=0.045%
(0.1)/(4.7)×100=2.13%
Idea: the coarser measurement dominates; the volume term is nearly fifty times the mass term.
Total =0.045+2.13=2.17≈2%
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