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Asked in NEET 2023 · Percentage error in a derived quantity
Given: m=(0.4±0.002) g, r=(0.3±0.001) mm, l=(5±0.02) cm.
ρ=m/(π r²l)
Idea: the radius is squared, so its fractional error counts twice.
(Δρ)/ρ=(Δ m)/m+2(Δ r)/r+(Δ l)/l
(0.002)/(0.4)×100=0.5%
2×(0.001)/(0.3)×100=0.67%
(0.02)/5×100=0.4%
Total =0.5+0.67+0.4=1.57≈1.6%
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