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A metal wire has mass (0.4±0.002) g, radius (0.3±0.001) mm and length (5±0.02) cm. The maximum possible percentage error in the measurement of density will nearly be

Asked in NEET 2023 · Percentage error in a derived quantity

Answer: (2) 1.6%

Step-by-step solution

Given: m=(0.4±0.002) g, r=(0.3±0.001) mm, l=(5±0.02) cm.

ρ=m/(π r²l)

Idea: the radius is squared, so its fractional error counts twice.

(Δρ)/ρ=(Δ m)/m+2(Δ r)/r+(Δ l)/l

(0.002)/(0.4)×100=0.5%

2×(0.001)/(0.3)×100=0.67%

(0.02)/5×100=0.4%

Total =0.5+0.67+0.4=1.57≈1.6%

Why the other options are wrong

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