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Consider the junction diode as ideal. The value of the current flowing through AB is

Asked in NEET 2016 (Phase I) · Circuits with diodes

Figure: Circuits with diodes
Answer: (4) 10⁻² A

Step-by-step solution

Idea: an ideal diode that is forward biased has no resistance at all, so the whole potential difference falls on the resistor.

Check the bias: A is at +4 V on the p-side and B at -6 V on the n-side, so the diode is forward biased and conducts.

Potential difference across the pair: V_A-V_B=4-(-6)=10 V.

All of it appears across the 1 kΩ resistor, so I=(10)/(1000).

I=10⁻² A.

Why the other options are wrong

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