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Asked in NEET 2016 (Phase I) · Circuits with diodes
Idea: an ideal diode that is forward biased has no resistance at all, so the whole potential difference falls on the resistor.
Check the bias: A is at +4 V on the p-side and B at -6 V on the n-side, so the diode is forward biased and conducts.
Potential difference across the pair: V_A-V_B=4-(-6)=10 V.
All of it appears across the 1 kΩ resistor, so I=(10)/(1000).
I=10⁻² A.
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