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Asked in NEET 2025 · Conservation of angular momentum
Given: T=27 days, radius doubled, mass unchanged, no external torque.
Idea: with no external torque the angular momentum L=Iω is conserved.
For a uniform sphere I=2/5MR², so at fixed M, I∝ R².
Iω=I'ω' with I'=4I gives ω'=ω/4.
T=(2π)/ω, so T'=4T.
T'=4×27=108 days.
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