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A thin horizontal disc is rotating about a vertical axis passing through its fixed centre O. Its angular momentum is L_A and L_B computed about points A and B, respectively, with OB=2× OA. The value of (L_A)/(L_B) is :

Asked in Re-NEET 2026 · Angular momentum of a rigid body

Figure: Angular momentum of a rigid body
Answer: (3) 1

Step-by-step solution

About any point P: ⃗L_P=⃗L_cm+⃗r_P→cm× M⃗v_cm.

The centre O is fixed, so ⃗v_cm=0 and ⃗L_P=⃗L_cm=(MR²)/2ω for every point.

L_A=L_B, so (L_A)/(L_B)=1.

Why the other options are wrong

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