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A round disc of moment of inertia I₂ about its axis perpendicular to its plane and passing through its centre is placed over another disc of moment of inertia I₁ rotating with an angular velocity ω about the same axis. The final angular velocity of the combination of discs is

Asked in CBSE AIPMT 2004 · Conservation of angular momentum

Answer: (3) (I₁ω)/(I₁+I₂)

Step-by-step solution

Given: a disc I₁ spinning at ω; a disc I₂ at rest placed on it, coaxially.

Idea: the friction that brings them to a common speed is internal, so angular momentum about the axis is conserved.

Lᵢ=I₁ω+I₂(0)=I₁ω

L_f=(I₁+I₂)ω'

I₁ω=(I₁+I₂)ω'

ω'=(I₁ω)/(I₁+I₂)

Check: with I₂=0 this returns ω, as it must.

Why the other options are wrong

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